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shalvi
Nervous Wreck (II) Inmate

From:
Insane since: Oct 2003

posted posted 11-06-2003 20:56

here the syntax is okk...but the code does not get any value....is there any problem in the LIKE ?help...

code
_____________________________________________________________________
user = mysql_query("SELECT Fname,Lname,
Tel,address,level,cityname,subj
FROM detail,city,subject
WHERE detail.AID=city.AID
AND city.AID=subject.AID AND cityname='$cityname' AND subj LIKE '$subjectid' ");

Emperor
Maniac (V) Mad Scientist with Finglongers

From: Cell 53, East Wing
Insane since: Jul 2001

posted posted 11-06-2003 21:02

shalvi: If you are taking data from multiple tables you should specify the table names like detail.FName, etc.

___________________
Emps

The Emperor dot org

Tyberius Prime
Paranoid (IV) Mad Scientist with Finglongers

From: Germany
Insane since: Sep 2001

posted posted 11-06-2003 22:04

actually, emps that's wrong: You only have to specify them when their ambigious.

Your problem, shalvi, is that LIKE 'something' works like = 'something'. You'll need to add placeholders (usally % - any character - any number of times, or no charater), either at the beginning or at the end, or both.

The manual would've told you.

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