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Hiroki Paranoid (IV) Inmate From: NZ Insane since: Dec 2002	posted 08-21-2003 00:15 Hi, guys. How are you? Well, I have been trying to understand the concept about XSLT. It is a language for transforming XML document. XML is not predefined so that browser doesn't understand how to display nicely. Just like HTML and CSS. So I have to make up XSL template to show content. In that template, I can put style(actually CSS?!) into each tag of template. After that put path in XML file to connect XSL file and XML file. In this way, I can see well-formatted XML using browser. What I was wondering was: When I make XSL template, I wanted to take CSS styles into external stylesheet. Cuz I felt like doing inline format. When I format HTML file, I avoid inline format. I was pretty confused about that. But actually XSLT is the stylesheet which looks after stylesheet as well as structure(template). Hhmm.....Difficult to explain..... I need to study more English though. Anyway, do you know what I mean???? If so, what do you think? Hiroki Kozai
Moon Shadow Paranoid (IV) Inmate From: Rouen, France Insane since: Jan 2003	posted 08-21-2003 13:07 If I understood well your question (which I'm not sure, I too have problems with English ), you want to include CSS styles in your XSL files ? You can. An example from this page, I added the bolded part : code: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <html> [b]<head> <link href="css.css" rel="stylesheet" type="text/css" /> </head>[/b] <body> <h2>My CD Collection</h2> <table border="1"> <tr bgcolor="#9acd32"> <th align="left">Title</th> <th align="left">Artist</th> </tr> <xsl:for-each select="catalog/cd"> <tr> <td [b]class="title"[/b]><xsl:value-of select="title"/></td> <td><xsl:value-of select="artist"/></td> </tr> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet> The bolded parts will result in applying the class "title" defined in css.css. [This message has been edited by Moon Shadow (edited 08-21-2003).]
Hiroki Paranoid (IV) Inmate From: NZ Insane since: Dec 2002	posted 08-22-2003 06:32 First of all, thanks for your reply. I regretted about submitting that post. Well, feel like wondering around in the dark. Cannot see anything..... @_@ Hmm...... Hiroki Kozai

Topic: XSL Stylesheet seems to be inline format... (Page 1 of 1) $Pages that link to <a href="https://ozoneasylum.com/backlink?for=11029" title="Pages that link to Topic: XSL Stylesheet seems to be inline format... (Page 1 of 1)" rel="nofollow" >Topic: XSL Stylesheet seems to be inline format... <span class="small">(Page 1 of 1)</span>\$

Hiroki
Paranoid (IV) Inmate

From: NZ
Insane since: Dec 2002

posted 08-21-2003 00:15

Hi, guys. How are you?
Well, I have been trying to understand the concept about XSLT.
It is a language for transforming XML document.
XML is not predefined so that browser doesn't understand how to display nicely.
Just like HTML and CSS. So I have to make up XSL template to show content. In that template, I can put style(actually CSS?!) into each tag of template.
After that put path in XML file to connect XSL file and XML file.
In this way, I can see well-formatted XML using browser.

What I was wondering was:
When I make XSL template, I wanted to take CSS styles into external stylesheet. Cuz I felt like doing inline format. When I format HTML file, I avoid inline format. I was pretty confused about that.

But actually XSLT is the stylesheet which looks after stylesheet as well as structure(template).

Hhmm.....Difficult to explain.....
I need to study more English though.
Anyway, do you know what I mean????
If so, what do you think?

Hiroki Kozai

Moon Shadow
Paranoid (IV) Inmate

From: Rouen, France
Insane since: Jan 2003

posted 08-21-2003 13:07

If I understood well your question (which I'm not sure, I too have problems with English ), you want to include CSS styles in your XSL files ?

You can.

An example from this page, I added the bolded part :

code:

<xsl:stylesheet version="1.0"

xmlns:xsl="http://www.w3.org/1999/XSL/Transform">



<xsl:template match="/">

  <html>

  [b]<head>

   <link href="css.css" rel="stylesheet" type="text/css" />

   </head>[/b]

  <body>

    <h2>My CD Collection</h2>

    <table border="1">

    <tr bgcolor="#9acd32">

      <th align="left">Title</th>

      <th align="left">Artist</th>

    </tr>

    <xsl:for-each select="catalog/cd">

    <tr>

      <td [b]class="title"[/b]><xsl:value-of select="title"/></td>

      <td><xsl:value-of select="artist"/></td>

    </tr>

    </xsl:for-each>

    </table>

  </body>

  </html>

</xsl:template>



</xsl:stylesheet>

The bolded parts will result in applying the class "title" defined in css.css.

[This message has been edited by Moon Shadow (edited 08-21-2003).]

Hiroki
Paranoid (IV) Inmate

From: NZ
Insane since: Dec 2002

posted 08-22-2003 06:32

First of all, thanks for your reply.
I regretted about submitting that post.
Well, feel like wondering around in the dark.
Cannot see anything.....
@_@ Hmm......

Hiroki Kozai

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