Topic: XML file to 'nested' list? (Page 1 of 1)

<menu>

	<menuitem>

		<name>Products</name>

		<link>#</link>

			<menuitem>

				<name>Printing</name>

				<link>#</link>

			</menuitem>

			<menuitem>

				<name>Whatever</name>

				<link>#</link>

					<menuitem>

						<name>Whatever-Sub</name>

						<link>#</link>

					</menuitem>



			</menuitem>



	</menuitem>

</menuitem>

<xsl:for-each select="menu/menuitem">



	  </xsl:for-each>

		<script>

	var oMenu1 = new Menu();

      <xsl:for-each select="menu/menuitem">

		<xsl:if test="count(menuitem) = 0">

	var oMenu1A = oMenu1.CreateLink();

	oMenu1A.displayHtml = "<xsl:value-of select="name" />";

	oMenu1A.href = "<xsl:value-of select="link" />";

			</xsl:if>

	<xsl:if test="count(menuitem) > 0">



		

	var oMenu1B = oMenu1.CreateMenu();

	oMenu1B.displayHtml = "<xsl:value-of select="name" />";

	        <xsl:for-each select="menuitem">

			var oMenu1B_a = oMenu1.CreateLink();

			oMenu1B_a.displayHtml = "<xsl:value-of select="name" />";

			oMenu1B_a.href = "<xsl:value-of select="link" />";

			oMenu1B.AddItem(oMenu1B_a);



	  		</xsl:for-each>

	oMenu1.AddItem(oMenu1B);

		</xsl:if>

				<xsl:if test="count(menuitem) = 0">

	oMenu1.AddItem(oMenu1A);

	</xsl:if>

	    </xsl:for-each>

<ul>



<xsl:for-each select="menu/menuitem">



<ul>

	<li><xsl:value-of select="name" /></li>

	<li><xsl:value-of select="link" /></li>	



</xsl:for-each>



</ul>          

....                

</ul>           

</ul> 



(write he number of </ul> you need)