Topic awaiting preservation: perl directories RE (Page 1 of 1)

I have a list of directories that I need to change from /foo/bar to ../../ (for each folder, I want to replace the scalar with ../ )

What is the simplest RE to do this? I was thinking something like s/(\/.*)(.*)/..\/${2}/i;

But that would probably turn /foo/bar into ../ since perl is "greedy" Is there a better way that "\/[all chars except/]*(.*)"

If that makes sense, thanks for the help.

to quote perl.com http://www.perl.com/doc/manual/html/pod/perlre.html

quote:

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By default, a quantified subpattern is ``greedy'', that is, it will match as many times as possible (given a particular starting location) while still allowing the rest of the pattern to
match. If you want it to match the minimum number of times possible, follow the quantifier with a ``?''. Note that the meanings don't change, just the ``greediness''

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All clear?

That looks like what I need, but I am still having trouble. I think I am overcomplicating the RE. I want to replace ever /foo with ../

Here's what I have, but, it only prepends the directory with ../

$img_path =~ s/(\/.*?)(.*)/\.\.\/$2/g;

thanks

well... Why do you do this with regexps anyhow.
Why don't you do a 'while there's a / in string' 'cut off till next slash' add '../' to new string, when done add rest to new string?