Preserved Topic: how do you round to 2 decimal places? (Page 1 of 1)

how do you round to 2 decimal places?

"there has to be a solution."

The poster has demanded we remove all his contributions, less he takes legal action.
We have done so.
Now Tyberius Prime expects him to start complaining that we removed his 'free speech' since this message will replace all of his posts, past and future.
Don't follow his example - seek real life help first.

Personally, I'd multiply by 100, round off (Math.round()), and then divide by 100.

function roundoff(num, decimalplaces)
{
var decimalfactor = Math.pow(10,decimalplaces);
return Math.round(num*decimalplaces)/decimalplaces;
}

if you were to multiply and divide by 100, in the case of a '0' ending up at the end (for example, 12.50), it would show up as 12.5 and not 12.50. i need to maintain a consistency with regards to the monetary figures.

"there has to be a solution."

actually, i did a little indexOf workaround magic and solved my problem. thanks for the head start slime!

-gerald

"there has to be a solution."

oh come on hecster... how am I suppose to learn from what you did if you don't post it?

Please everyone, always post your solution so as to not hang later readers out to dry.

Thanks.

hmm... I didn't know IE had implemented .toFixed but it seems to work.

function precise(num,X) { //num to X decimal places, defaults to 2

	X = (!X ? 2 : X);

	if(Number.prototype.toFixed)

		return num.toFixed(X);

	else

		return Math.round(num*Math.pow(10,X))/Math.pow(10,X);

}

When given 123.4 the above function should give back 123.40 for more current browsers that implement Number.toFixed and 123.4 for older ones.



[This message has been edited by genis (edited 09-19-2002).]

um... I don't know much about the "Math.round()" function, but shouldn't it do something like " Math.round(-2)" for two decimal places?


Code - CGI - links - DHTML - Javascript - Perl - programming - Magic - http://www.twistedport.com
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Math.round() just rounds a number; for instance, Math.round(1.3) returns 1, and Math.round(5.7) returns 6.

BTW petskull: I dropped Trillian at least for now 'cause I didn't like the interface. Sorry... =)

no prob, dude... you want that ol' version of ICQ98?


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ICQ: 67751342

No thanks, I think I had that originally, didn't really like *it* either =)

oh, oops ... hehe. here, have a look. it seems to do the trick for me. added a little more code to Slime's code.

function roundOff(num, decimalplaces)

	{

		var decimalfactor = Math.pow(10,decimalplaces);

		roundedValue = Math.round(num*decimalfactor)/decimalfactor;

		strVal = roundedValue.toString();



		if (strVal.indexOf(".") == -1)

			roundedValue += ".00";

		else if (strVal.substring(strVal.indexOf(".")+1,strVal.length).length < 2)

			roundedValue += "0";

		

		return roundedValue;

	}

"there has to be a solution."

Would this do ? :
x = parseInt((x*100))\100;