Topic awaiting preservation: Advanced CPP question (Page 1 of 1)

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If it works let it be. You can always force it one way or the other with compiler options.

Dan @ Code Town

#define   byte unsigned char

#define   word unsigned short

#define  dword unsigned long



#define  sbyte  signed  char

#define  sword  signed  short

#define sdword  signed  long

Shazam!

The poster has demanded we remove all his contributions, less he takes legal action.
We have done so.
Now Tyberius Prime expects him to start complaining that we removed his 'free speech' since this message will replace all of his posts, past and future.
Don't follow his example - seek real life help first.

From your description it sounds as if you are just moving information into and out of the chars, not doing any arithmetic or other kinds of operations. As long as all you are doing is assigning and reading data, the sign of the char will make no difference.

The one place this is not true is when you move information from a signed char to a signed int and the sign bit is set in the char. This will cause the sign bit to be propagated in the int. This may also happen when moving to an unsigned int, but I don't remember for sure. You can, of course, stop the sign propogation by casting the char as an unsigned char when you make the assignment.

Anyway, the only time the sign of the char should be an issue is when the sign bit of a signed char is set (which it may be because you are using the char to store bytes, not characters). But even then it will not be an issue as long as you are doing I/O and assigning the data to other char data.



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-- not necessarily stoned... just beautiful.

The poster has demanded we remove all his contributions, less he takes legal action.
We have done so.
Now Tyberius Prime expects him to start complaining that we removed his 'free speech' since this message will replace all of his posts, past and future.
Don't follow his example - seek real life help first.