Topic awaiting preservation: PREG_REPLACE and escaping HTML tags (Page 1 of 1)

I couldn't find this is various searches, and realize I'm probably just not using the right keywords.

Anyways:

$code = preg_replace("<IMG height=23 src=\"images/printdoc.gif\" width=22 border=0>", "", $code);

I end up with '<>', since it doesn't seem to be escaping those characters. I'm not having any luck on getting it to strip everything. I need to do some more replacements that also involve HTML tags...

What am I missing? I looked up all the comments for preg_replace on php.net, but they didn't seem to help.

Thanks!

Pugzly: This should work:

$code = preg_replace("(<IMG height=23 src=\"images/printdoc.gif\" width=22 border=0> )si", "", $code);

but unless you were trying to do some more complex regular expression work:

$code = preg_replace("(<IMG height=23 src=\"images/(.*)\" width=22 border=0> )si", "", $code);

then I'd recommend you use a string function.

[edit: So it would be something like:

$code = str_replace("<IMG height=23 src=\"images/printdoc.gif\" width=22 border=0>", "", $code);

but it depends on your plans.]

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Emps

FAQs: Emperor

Basically doing some fairly simple web fetching and just need to strip out some unwanted tags, but can't strip them all (or I'd use strip_tags).

What's the 'si' do?

Pugzly: si are pattern modifiers:
http://www.php.net/manual/en/pcre.pattern.modifiers.php

i means it checks both cases

s means that the dot will also match a newline - not technically necessary in this case but I tend to throw it in just in case something odd is going on.

___________________
Emps

FAQs: Emperor