Topic awaiting preservation: SQL pro (Page 1 of 1)

Hi, guys. I have got a sql question. Please help me.

Here is data
col0, ID, col1, col2
----------------
1, a, 100, 0
2, a, 101, 0
3, a, 102, 0
4, b, 200, 0
5, b, 201, 0
6, b, 202, 1
7, c, 300, 0
8, c, 301, 0
9, c, 302, 0
-----------------

I want to extract all b. When each ID gets col2, which is "1", I want to show all data of that ID.
Hum..... Make sence????

In the case above, I want to show like below
------------------
b, 200
b, 201
b, 202
------------------

Not only
-----------------
b, 201
-----------------

Please help me.

Hiroki Kozai

(Edited by Hiroki on 06-23-2004 07:38)

SELECT ID,col1 FROM table_name WHERE ID = 'b' ???

I am having some trouble understanding what exactly you are asking for. That matches your pattern. If you could clarify gramatically what you are trying to do I am sure I could be of some more help.

Hi, thanks for your help.
Well, in my case, I have to check col2 if it is 1 or not. Then if col2 is 1, I want to show all the data of that ID's data.

For example,
----------------
1, a, 100, 0
2, a, 101, 0
3, a, 102, 0
4, b, 200, 0
5, b, 201, 0
6, b, 202, 1
7, c, 300, 0
8, c, 301, 0
9, c, 302, 0
10, d, 401, 0
11, d, 402, 0
12, d, 403, 1
-----------------

This case, I want to show below cuz b and c has col2,which is 1
-----------------
b, 200
b, 201
b, 202
d, 401
d, 402
d, 403
-----------------

many thanks in advance.
Cheers.

Becasue

Hiroki Kozai

Hiroki

In reading your explaination, it's still hard to understand what you're trying to do. You say you want to select those rows that have a col2 value of 1. In looking at your sample data only 2 enrtys match that:

b, 202
d, 403

but your showing 6 entries that you really want returned.

Can you try to clairify it yet a little more?

-Butcher-

(Edited by butcher on 06-24-2004 02:58)

My SQL is a little rusty, but I think your trying to do something like

SELECT ID,col1 FROM table_name WHERE ID in select ID from table_name where id = 1

-- not necessarily stoned... just beautiful.


(Edited by hyperbole on 06-24-2004 17:56)

Hi, guys. many thanks for your reply and sorry for my poor explanation.
hyperbole:
Yeah, it is what I wanted.
I could not understand 'in select'
I got the result right, but would you explain what in select do???
Again, many thanks for your replies.
I have been absent from this site for a while, but still keep doing this kind of things.
Cya.

Hiroki Kozai