Topic: change of column to row in xsl (Page 1 of 1) |
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Obsessive-Compulsive (I) Inmate From: |
posted 09-20-2006 09:31
I want to change the Xsl column data to XSL row |
Maniac (V) Mad Scientist From: Rochester, New York, USA |
posted 09-20-2006 16:41
How about you show us the starting XML and what you want the resultant XML to be? |
Obsessive-Compulsive (I) Inmate From: |
posted 09-21-2006 07:18
The Xml is as follows: code: <edocs:d-edocs-timesheet> <request-id>900687</request-id> <ccn>GEC</ccn> <mas-loc>M</mas-loc> <dept>5100</dept> <emp-num>2128</emp-num> <date-day>Monday</date-day> <rec-seq>1</rec-seq> <emp-name>SELLERS, WAYNE</emp-name> <shift>1</shift> <wo-num>769247</wo-num> <wo-line>0001</wo-line> <type->R</type-> <hours>8</hours> <operation> 20</operation> <comp-qty>122</comp-qty> </edocs:d-edocs-timesheet> <edocs:d-edocs-timesheet> <request-id>900687</request-id> <ccn>GEC</ccn> <mas-loc>M</mas-loc> <dept>5100</dept> <emp-num>2128</emp-num> <date-day>Monday</date-day> <rec-seq>2</rec-seq> <emp-name>SELLERS, WAYNE</emp-name> <shift>1</shift> <wo-num>769247</wo-num> <wo-line>0001</wo-line> <type->O</type-> <hours>2</hours> <operation> 20</operation> <comp-qty>30</comp-qty> </edocs:d-edocs-timesheet> <edocs:d-edocs-timesheet> <request-id>900687</request-id> <ccn>GEC</ccn> <mas-loc>M</mas-loc> <dept>5100</dept> <emp-num>2128</emp-num> <date-day>Tuesday</date-day> <rec-seq>3</rec-seq> <emp-name>SELLERS, WAYNE</emp-name> <shift>1</shift> <wo-num>769247</wo-num> <wo-line>0001</wo-line> <type->R</type-> <hours>3</hours> <operation> 20</operation> <comp-qty>10</comp-qty> </edocs:d-edocs-timesheet>
code: wo-line wo-order type mon tues wed thr fri ****** ******* ***** **** ****** *********************** 769247 0001 R 8 769247 0001 R 2 769247 0001 O 2
code: wo-line wo-order type mon tues wed thr fri ****** ******* ***** **** ****** *********************** 769247 0001 R 8 2 769247 0001 O 2
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Maniac (V) Inmate From: |
posted 09-21-2006 14:52
The xsl. Somewhere in your xsl code, you got a template that maps "stuff" to cols. xsl:template tags. Check the ones that match the "col" structure in your final xhtml document. And change the xhtml inside that. |
Maniac (V) Mad Scientist From: Rochester, New York, USA |
posted 09-21-2006 15:01
Note: I have added a root element doc and changed edocs:d-edocs-timesheet to timesheet in my example so that I did not have to worry about name space issues. code: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0"xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <html> <head></head> <body> <table> <thead> <tr> <th>wo-line</th> <th>wo-order</th> <th>type</th> <th>mon</th> <th>tue</th> <th>wed</th> <th>thur</th> <th>fri</th> </tr> </thead> <tbody> <xsl:for-each select="/doc/timesheet[not(wo-num = preceding::wo-num and wo-line = preceding::wo-line and type- = preceding::type-)]"> <xsl:variable name="wo-num" select="wo-num"/> <xsl:variable name="wo-line" select="wo-line"/> <xsl:variable name="type-" select="type-"/> <tr> <td><xsl:value-of select="wo-num"/></td> <td><xsl:value-of select="wo-line"/></td> <td><xsl:value-of select="type-"/></td> <xsl:for-each select="/doc/timesheet[wo-num = $wo-num and wo-line = $wo-line and type- = $type-]"> <td><xsl:value-of select="hours"/></td> </xsl:for-each> </tr> </xsl:for-each> </tbody> </table> </body> </html> </xsl:template> </xsl:stylesheet>
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