Topic awaiting preservation: php loop through database and limit number of entries? (Page 1 of 1) $Pages that link to <a href="https://ozoneasylum.com/backlink?for=30920" title="Pages that link to Topic awaiting preservation: php loop through database and limit number of entries? (Page 1 of 1)" rel="nofollow" >Topic awaiting preservation: php loop through database and limit number of entries? <span class="small">(Page 1 of 1)</span>\$

CPrompt Maniac (V) Inmate From: there...no..there..... Insane since: May 2001	posted 03-19-2009 01:53 Going to try to explain this as best I can. I have a bunch of stuff in a database and I need to display this info within a table. This isn't a problem at all but, I need it to only display 3 td tags per line and then move on to the row. so i need it to do : code: <table> <tr> <td>My First Row</td> <td>My First Row 2</td> <td>My First Row 3</td> </tr> <tr> <td>My Second Row</td> <td>My Second Row 2</td> <td>My Second Row 3</td> </tr> </table> and continue to do this through every entry in the database table. so I have something like this that will display the info: code: for ($i = 1; $i <= $num; $i++){ $chairArray = mysql_fetch_array($chairResult); $chairName = $chairArray['name']; $chairDescription = $chairArray['description']; $chairImage = $chairArray['image']; echo "<tr>"; echo "<td>"; echo "<img src=\"images/catalog/ottomans/thumbs/$chairImage\" width=\"157\" height=\"147\" />"; echo "<br />"; echo $chairName; echo "</td>"; echo "</tr>"; } Rough example So how can I make it do something like what I have and only display 3 per line? Thanks in advance!!! Later, C:\ (Edited by CPrompt on 03-19-2009 02:02)
Tyberius Prime Maniac (V) Mad Scientist with Finglongers From: Germany Insane since: Sep 2001	posted 03-19-2009 10:19 code: ?> <tr><td>header</td><td>header</td><td>header3</td><?php //no </tr>... for ($i = 1; $i <= $num; $i++){ $chairArray = mysql_fetch_array($chairResult); $chairName = $chairArray['name']; $chairDescription = $chairArray['description']; $chairImage = $chairArray['image']; if ($i % 3 == 0) { echo "</tr>"; echo "<tr>"; } echo "<td>"; echo "<img src=\"images/catalog/ottomans/thumbs/$chairImage\" width=\"157\" height=\"147\" />"; echo "<br />"; echo $chairName; echo "</td>"; } ?></tr><?php Might have to adjust it a little bit since you foolishly start counting at 1, but you get the general idea...
CPrompt Maniac (V) Inmate From: there...no..there..... Insane since: May 2001	posted 03-19-2009 12:14 thanks. quote: Tyberius Prime said: since you foolishly start counting at 1 I said it was a rough sketch ;-) Later, C:\
Karl Bipolar (III) Inmate From: Phoenix Insane since: Jul 2001	posted 03-23-2009 23:18 When the loop is done, do not neglect to deal with the remainder of 3, so if you looped once through the last mod 3 test, you'd have a remainder of 2, you'd need to either: a) colspan last td by remainder + 1 (well, depending on how you are counting) b) create each additional td giving it some empty value Karl..
CPrompt Maniac (V) Inmate From: there...no..there..... Insane since: May 2001	posted 03-24-2009 20:35 or just do code: for ($i = 0; $i <= $num -1; $i++){ Later, C:\

Topic awaiting preservation: php loop through database and limit number of entries? (Page 1 of 1) $Pages that link to <a href="https://ozoneasylum.com/backlink?for=30920" title="Pages that link to Topic awaiting preservation: php loop through database and limit number of entries? (Page 1 of 1)" rel="nofollow" >Topic awaiting preservation: php loop through database and limit number of entries? <span class="small">(Page 1 of 1)</span>\$

CPrompt
Maniac (V) Inmate

From: there...no..there.....
Insane since: May 2001

posted 03-19-2009 01:53

Going to try to explain this as best I can. I have a bunch of stuff in a database and I need to display this info within a table. This isn't a problem at all but, I need it to only display 3 td tags per line and then move on to the row.

so i need it to do :

code:

<table>
<tr>
<td>My First Row</td>
<td>My First Row 2</td>
<td>My First Row 3</td>
</tr>

<tr>
<td>My Second Row</td>
<td>My Second Row 2</td>
<td>My Second Row 3</td>
</tr>
</table>

and continue to do this through every entry in the database table.

so I have something like this that will display the info:

code:

for ($i = 1; $i <= $num; $i++){
	
		$chairArray = mysql_fetch_array($chairResult);
		$chairName = $chairArray['name'];
		$chairDescription = $chairArray['description'];
		$chairImage = $chairArray['image'];
		
		echo "<tr>";
		echo "<td>";
		echo "<img src=\"images/catalog/ottomans/thumbs/$chairImage\" width=\"157\" height=\"147\" />";
		echo "<br />";
		echo $chairName;
		echo "</td>";
		echo "</tr>";
		
		
	}

Rough example

So how can I make it do something like what I have and only display 3 per line?

Thanks in advance!!!

Later,

C:\

(Edited by CPrompt on 03-19-2009 02:02)

Tyberius Prime
Maniac (V) Mad Scientist with Finglongers

From: Germany
Insane since: Sep 2001

posted 03-19-2009 10:19

code:

?> <tr><td>header</td><td>header</td><td>header3</td><?php //no </tr>...
for ($i = 1; $i <= $num; $i++){
	
		$chairArray = mysql_fetch_array($chairResult);
		$chairName = $chairArray['name'];
		$chairDescription = $chairArray['description'];
		$chairImage = $chairArray['image'];
		if ($i % 3 == 0)
{
     		        echo "</tr>";
                 		echo "<tr>";
}
		echo "<td>";
		echo "<img src=\"images/catalog/ottomans/thumbs/$chairImage\" width=\"157\" height=\"147\" />";
		echo "<br />";
		echo $chairName;
		echo "</td>";
		
	}
?></tr><?php

Might have to adjust it a little bit since you foolishly start counting at 1, but you get the general idea...

CPrompt
Maniac (V) Inmate

From: there...no..there.....
Insane since: May 2001

posted 03-19-2009 12:14

thanks.

quote:

Tyberius Prime said:

since you foolishly start counting at 1

I said it was a rough sketch ;-)

Later,

C:\

Karl
Bipolar (III) Inmate

From: Phoenix
Insane since: Jul 2001

posted 03-23-2009 23:18

When the loop is done, do not neglect to deal with the remainder of 3, so if you looped once through the last mod 3 test, you'd have a remainder of 2, you'd need to either:

a) colspan last td by remainder + 1 (well, depending on how you are counting)
b) create each additional td giving it some empty value

Karl..

CPrompt
Maniac (V) Inmate

From: there...no..there.....
Insane since: May 2001

posted 03-24-2009 20:35

or just do

code:

for ($i = 0; $i <= $num -1; $i++){

Later,

C:\