Topic awaiting preservation: simple javascript function question (Page 1 of 1)

ok so I have a javascript function. It does a lot of different things, and for one of this things I want to be able to include another argument, but none of the others need it, so it would be a hassle to have it in every call of the function, so I was wondering if there was a way I could make the argument optional. I know there's ways to do this in other scripting languages, but I've never come across it in javascript. Does it exist, and if so how would I accomplish this?

http://www.kewlster.com

Post your code - that may help us.

In JavaScript, all arguments are automatically optional. If an argument isn't specified, it will have the undefined value inside the function. For instance, the following function

function myfunc(a, b, c)
{
...
}

can be called in any of the following ways:

myfunc(); // a b and c will be undefined
myfunc(1,2); // c will be undefined
myfunc(1,,3); // b will be undefined
myfunc(1,2,3,4,5,6,7); a, b, and c will be defined; to get access to the rest of the arguments, use the arguments[] array accessed from inside the function.

Thanks Slime,
I didn't know that.

http://www.kewlster.com

Javascript is just that... "script". It is much less strict than full up programming languages like c++. And thankfully so for what it's intended to do.

On the other hand, that enables it to have things like the eval() function, which are amazingly overused... and it's slower too; much slower than a real, compiled, language. So, advantages and disadvantages, really. Compiled languages tend to have more low-level things that give you ways of getting around the lack of an eval() function or the [] operator for indirection.